用编程判断闰年

编程实现闰年的判断

在很多编程任务中，需要判断给定的年份是否是闰年。闰年的定义是能被4整除但不能被100整除的年份，或者能被400整除的年份。下面是几种常见编程语言的实现示例：

1. Python

```python

def is_leap_year(year):

if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):

return True

else:

return False

year = 2024

if is_leap_year(year):

print(f"{year}年是闰年")

else:

print(f"{year}年不是闰年")

```

2. Java

```java

public class LeapYear {

public static boolean isLeapYear(int year) {

return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);

}

public static void main(String[] args) {

int year = 2024;

if (isLeapYear(year)) {

System.out.println(year "年是闰年");

} else {

System.out.println(year "年不是闰年");

}

}

}

```

3. JavaScript

```javascript

function isLeapYear(year) {

return (year % 4 === 0 && year % 100 !== 0) || (year % 400 === 0);

}

let year = 2024;

if (isLeapYear(year)) {

console.log(`${year}年是闰年`);

} else {

console.log(`${year}年不是闰年`);

}

```

4. C

```cpp

include

using namespace std;

bool isLeapYear(int year) {

return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);

}

int main() {

int year = 2024;

if (isLeapYear(year)) {

cout << year << "年是闰年" << endl;

} else {

cout << year << "年不是闰年" << endl;

}

return 0;

}

```

5. C

```csharp

using System;

class Program {

static bool IsLeapYear(int year) {

return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);

}

static void Main(string[] args) {

int year = 2024;

if (IsLeapYear(year)) {

Console.WriteLine($"{year}年是闰年");

} else {

Console.WriteLine($"{year}年不是闰年");

}

}

}

```

以上是几种常见编程语言的闰年判断实现。根据需要选择合适的语言和方法进行实现。